Question

6g of Mg reacts with excess of an acid . The amount of hydrogen produced would be

Answer 1

Answer:

The answer is 0.5g this is the correct answer

Answer 2

Answer: 0.50 g

Explanation:

$Mg+2HCl\rightarrow MgCl_2+H_2$

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

$\text{Number of moles of magnesium}=\frac{6g}{24g/mol}=0.25moles$

According to stoichiometry:

1 mole of $Mg$ react with 2 moles of $HCl$

0.25 moles of $Mg$ will react with=$\frac{2}{1}\times 0.25=0.50moles$ of $HCl$

As $HCl$ is the excess reagent and thus $Mg[/tex[ is the limiting reagent as it limits the formation of product.</p><p>1 mole of [tex]Mg$ produces 1 mole of $H_2$

0.25 moles of $Mg$ produces=$\frac{1}{1}\times 0.25=0.25moles$ of $H_2$

Mass of $H_2$ =$moles\times {\text {Molar mass}}=0.25\times 2=0.50g$

Thus 0.50 g of $H_2$ will be produced.