Question

6grams of urea is dissolved in 90grams of water. The molefration of solute is​

Answer 1

Answer:

♡Mass of solute (urea)= 6gm

♡Mass of solvent(water)=90gm

♡ molar mass of urea NH2CONH2

= 14+(2×1)+12+16+14+(2×1) =60

♡NO. Of moles(n)of urea

= givenmass÷ molar mass

= 6÷60= 0.1

♡no. Of moles(n) of water

=given mass ÷ molar mass

= 90÷18 = 5

♡ molefraction

= no of moles of urea ÷ total moles

= 0.1 ÷(0.1 +5)

= 0.019

Answer 2

Hey!

• Solute : It is a substance present in less quantity in a solution, here solute is urea.

• First of all I will find moles of the given samples.

° Moles, n = m/M °

° For urea,

• Mass of urea = 6 grams

• Molar mass of urea = 60 grams/mole

• n = 6 / 60

• n = 0.1 mole •

° For water,

• Mass of water = 90 grams

• Molar mass of water = 18 grams/mole

• n = 90/18

• n = 5 moles •

Now, I will find molefraction of solute, i.e., urea.

• X(urea) = n(urea) / n(water) + n(urea)

• X(urea) = 0.1 / 5 + 0.1

• X(urea) = 0.1 / 5.1

• X(urea) = 0.01960784314 or 0.02 •

Hope it helps!