Question

6hx + 12ky +9kx +8hy factorise

Answer 1

Step-by-step explanation:

k(12y2+8y−20)

4k(3y2+2y−5)

4k(3y2+5y−3y−5)

⟹4k(y−1)(3y+5)

do like this to that

Answer 2

Answer:

The answer is $(3x+4y)(2h+3k)$

Step-by-step explanation:

Given expression is

   $=6hx+12ky+9kx+8hy$

Group the terms and factorize them

   $=(6hx+8hy)+(12ky+9kx)\\=2h(3x+4y)+3k(4y+3x)$

Factor out the common term

   $=(3x+4y)(2h+3k)$