Question

• 6j-k=23
3k+6j=11
solve this using elimination method , solve each of the following pairs of simultaneous equation .


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Answer 1

Answer:

Here is your required answer

Answer 2

Step-by-step explanation:

6j-k =23

6j+3k=11

chane the sign

6j is cancel

-4k=-12

minus is cancal

k= 12/4

k=3

subsutie k=3 in eqn 1

6j-k=23

6j-3=23

6j = 23+3

6j = 26

j = 26÷6

j=4.333