Question

6k − 2{k + 4 – 2 [2k – 1 – 2(1− k)]}.
Please explain With Clear Lines Of reasoning.
The one with answer and reasoning will be marked as brainliest

Answer 1

Step-by-step explanation:

$6k - 2(k + 4 - 2(2k - 1 - 2(1 - k)))$

4-2 = 2, -1-2 = 3

$= 6k - 2(k + 2(2k - 3(1 - k)))$

We have to multiply -3 with (1 - k)

$=6k - 2(k + 2(2k - 3 + 3k))$

2k + 3k = 5k

$= 6k - 2(k + 2(5k - 3))$

We have to multiply 2 with (5k - 3)

$= 6k - 2(k + 10k - 6)$

k + 10k = 11k

$= 6k - 2(11k - 6)$

We have to multiply -2 with (11k - 6)

$= 6k - 22k + 12$

6k - 22k = -16k

$= - 16k + 12$

We have to take out common.. So -4 is common.

$= - 4(4k - 3)$

Answer 2

Step-by-step explanation:

Refer to the attachments........

Hope it helps you....