6k2+11k−10=0 find k
please help help
Answers
Answered by
1
Answer:
k=⅔
Step-by-step explanation:
6k²+11-10=0
6k²-4k+15k-10=0
(6k²-4k)+(15k-10)=0
2k(3k-2)+5(3k-2)=0
(3k-2)(2k+5)=0
(3k-2=0)(2k+5=0)
k=⅔ and k=(-2/5)
Therefore, k=⅔
Answered by
0
6k2+11k-10=0
6k2+15k-4k-10=0
3k(2k+5)-2(2k+5)=0
(2k+5)(3k-2)=0
2k+5=0
k=-5/2
3k-2=0
k=2/3
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