Question

6kJ heat is provided to a system as well as work equivalent to 2kJis done on the system. The total change in internal energy during these operations in kJ is 10x .what is x

Answer 1

Answer:

x is the alphabet letter and y only find x

Explanation:

its very easy

Answer 2

x is 0.8 kJ

Explanation:

According to first law of thermodynamics:

$\Delta E=q+w$

$\Delta E$=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done on the system=$-P\Delta V$  {Work done on the system is positive as the final volume is lesser than initial volume}

w =$+2kJ$

q = +6kJ   {Heat absorbed by the system is positive}

$\Delta E=+6+(+2)=+8kJ$

Given $\Delta E=10x$

$10x=+8kJ$

$x=0.8kJ$

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