Question

6l {m }^{2} + 30 {l}^{2} m + {m}^{3} + 5l {m}^{2}6lm2+30l2m+m3+5lm2
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Answer 1

Answer ♡

Given

Perimeter of Rectangle is 60m

length is 4m more than four times it's breadth

To findi

length and breadth of the Rectangle

Slove

Let us assume the breadth of Rectangle be 'x'

according to the question

length would be => 4m+4x

Perimeter is 60m

Perimeter of Rectangle=2(length+Breadth)

=>60= 2( 4+4x +x)

=>60=2(4+5x)

=>2(4+5x)=60

=>4+5x=30

=>5x= 30-4

=>5x= 26

=>x= 26÷ 5

=>x=5.2

Now , breadth is 5.2m

length = 4+4x=4+4×5.2

length= 4+20.8=24.8m

Check

Perimeter of Rectangle=2( 24.8+5.2)

Perimeter of Rectangle=2(30)

Perimeter of Rectangle= 60m

Extra information=>

Perimeter is the total distance occupy by a solid 2D figure around its edge.

Area of Rectangle= length × breadth

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Answer 2

Answer:

6lm² + 30l²m + m³ + 5lm²

Step-by-step explanation:

we have to arrange like terms

6lm² + 5lm² +30l²m +m³

11lm² + 30l²m + m³

So the ans is

11lm² + 30l²m + m³