Question

6m 40cm high pole casts a shadow 4m 80cm long find:
a) The length of Shadow cast by another pole 12 cm 80 high
b) The height of a pole which casts a shadow 2m 40cm

i need it in step by step
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Answer 1

Answer:

Height of pole=AB=6 m

Length of shadow of pole =BC=4 m

Length of shadow of tower=EF=28 m

In △ABC and △DEF

∠B=∠E=90

∘

both 90

∘

as both are vertical to ground

∠C=∠F (same elevation in both the cases as both shadows are cast at the same time)

∴△ABC∼△DEF by AA similarity criterion

We know that if two triangles are similar, ratio of their sides are in proportion

So,

DE

AB

=

EF

BC

⇒

DE

6

=

28

4

⇒DE=6×7=42 m