Math, asked by djalok0503, 2 months ago


6m²n+5mn-n²,n²+mn-2m²and-3mn+3n²-4m²n​

Answers

Answered by nannuprajapati386175
3

this is your answer

Step-by-step explanation:

i hope help

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Answered by IntrovertLeo
9

Given:

  • 6m²n + 5mn - n²
  • n² + mn - 2m²
  • -3mn + 3n² - 4m²n​

What To Find:

The Sum of the above expressions.

Solution:

(6m²n + 5mn - n²) +  (n² + mn - 2m²) + (-3mn + 3n² - 4m²n​)

Remove the brackets,

⇒ 6m²n + 5mn - n² +  n² + mn - 2m² - 3mn + 3n² - 4m²n​

Rearrange the like terms,

6m²n - 4m²n​  - n² +  n² + 3n²  - 2m² - 3mn + 5mn + mn

Solve the first term,

⇒ 2m²n - n² +  n² + 3n²  - 2m² - 3mn + 5mn + mn

Solve the second term,

⇒ 2m²n + 3n² - 2m² - 3mn + 5mn + mn

Leave the third term as it is,

⇒ 2m²n + 3n² - 2m² - 3mn + 5mn + mn

Solve the fourth term,

⇒ 2m²n + 3n² - 2m² - 3mn

∴ So, the sum of the expression is 2m²n + 3n² - 2m² - 3mn.

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