Math, asked by singhs36891, 11 days ago

6n^3-n-19n^2-2n/2n-3
6n {}^3{} - n - 19n {}^{2} - 2r   \div 2n - 3

Answers

Answered by Jiya0071
1

Answer:

6n^3-n-19n^2-2n/2n-3</p><p>6n {}^3{} - n - 19n {}^{2} - 2r \div 2n - 3</p><p>

Hence the other factor is x² - 4 .

Answered by Rina86169
0

Answer:

6n^3-n-19n^2-2n/2n-3

6n {}^3{} - n - 19n {}^{2} - 2r \div 2n - 3

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