Question

6n²-14n +28 how can we split it.​

Answer 1

Step-by-step explanation:

6n²-14n+28

all the quadratic eq are of the form an²+bn+c

so for finding there root u can use the formula

$(- b + \sqrt{ {b}^{2} - 4ac } ) \div 2a$

or

$(- b - \sqrt{ {b}^{2} - 4ac } ) \div 2a$

using these two formula you can easily find out roots of any quadratic equation. And from any I mean any question even of the level of competitive examination like jee or neet and many more.

(In your question just put a=6,b=-14,c=28 you will get your answer)

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