Question

6p^2+17p+12 solve by middle term splitting

Answer 1

Answer:

(2p+3)(3p+4)

Step-by-step explanation:

6p2+8p+9p+12

2p(3p+4)+3(3p+4)

Answer 2

Answer

The zeroes of the given polynomial are -3/2 and -4/3

Step by step explanation

Given the quadratic polynomial is

6p² + 17p + 12

Splitting the middle term and factorizing we have

6p² + 17p + 12

= 6p² + 9p + 8p + 12

= 3p(2p + 3) + 4(2p + 3)

= (2p + 3)(3p + 4)

Now the zeroes of the polynomial are

2p +3 = 0

⇒2p = -3

⇒p = -3/2

and

3p + 4 = 0

⇒ 3p = -4

⇒p = -4/3