Question

6pencils and 5pens together cost 56.express this situation as linear equation in two variables
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Answer 1

Answer:

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Answer 2

Answer:

brainiest

Step-by-step explanation:

Let cost of one pen = x

cost of one pencil = y

5 pens and 6 pencils cost Rs. 9

⇒ 5x + 6y = 9 ....................(1)

⇒ 5x = 9 - 6y

⇒ x = (9-6y)/5

3 pens and 2 pencils cost Rs 5

⇒3x + 2y = 5

⇒3(\frac{9-6y}{5}

5

9−6y

) + 2y = 5

⇒\frac{27}{5} - \frac{18y}{5} +2y = 5

5

27

−

5

18y

+2y=5

⇒27 -18y +10y = 5*527−18y+10y=5∗5

⇒27 -8y = 2527−8y=25

⇒ \begin{gathered}-8y = 25-27 =-2 \\ y =(-2)/(-8) = 0.25\end{gathered}

−8y=25−27=−2

y=(−2)/(−8)=0.25

x = (9-6y)/5 = (9-6(1/4))/5 = 7.5/5 = 1.5(9−6y)/5= (9−6(1/4))/5=7.5/5=1.5

Cost of one pen = Rs. 1.5

Cost of one Pencil = Rs. 0.25

So cost of one pen and one pencil = 1.5+0.25 = Rs 1.75