Question

6pr=36 and 6cr=15 then find r!

Answer 1

Heya User,

[tex]^6C_r = \frac{^6P_r}{r!} \\ \\ =\ \textgreater \ 15 = \frac{36}{r!} \\ \\ which implies r! = 2.4 , which means no such soln. exist[/tex]

Answer 2

Answer:

12/5

Step-by-step explanation:

Since,

$^6C_r=\frac{6!}{r!(6-r)!}$ ------(1),

Also,

$^6P_r=\frac{6!}{(6-r)!}$ -----(2),

Dividing equation (1) by (2),

$\frac{^6C_r}{^6P_r}=\frac{1}{r!}$

$r!=\frac{^6P_r}{^6C_r}$

Given,

$^6P_r=36$ and $^6C_r=15$

$\implies r! = \frac{36}{15}=\frac{12}{5}$