Math, asked by hackerbinit7, 8 months ago

6root3+ 6root3÷6root3-6roo3​

Answers

Answered by ihrishi
1

Answer:

6 \sqrt{3} + 6 \sqrt{3} \div 6 \sqrt{3} - 6 \sqrt{3} \\ = 6 \sqrt{3} + \frac{6 \sqrt{3} }{6 \sqrt{3} } - 6 \sqrt{3} \\ = 6 \sqrt{3} + 1 - 6 \sqrt{3} \\ = 1

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