Math, asked by hackerbinit7, 10 months ago

6root3+ 6root3÷6root3-6roo3​

Answers

Answered by ihrishi
1

Answer:

6 \sqrt{3}  + 6 \sqrt{3}  \div 6 \sqrt{3}  - 6 \sqrt{3}  \\  = 6 \sqrt{3}  + \frac{6 \sqrt{3} }{6 \sqrt{3} }  - 6 \sqrt{3} \\  = 6 \sqrt{3}   + 1 - 6 \sqrt{3}  \\  = 1

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