6sec . Its speed was its passes the second point is 45m/a. What is its acceleration and the speed at the first point
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Answer:
Answer and Explanation:
The distance travelled is,
s
=
180
m
.
The time taken is,
t
=
6
s
.
The velocity is,
v
=
45
m
/
s
.
The expression for the initial velocity is given as,
u
=
v
−
a
t
Here,
a
is the acceleration.
Substituting the values in the above expression,
u
=
45
−
6
a
The expression for the acceleration is given as,
a
=
2
(
s
−
u
t
)
t
2
Substituting the values in the above expression,
a
=
2
(
180
−
(
45
−
6
a
)
6
)
6
2
18
a
=
36
a
−
180
a
=
10
m
/
s
2
Thus, the acceleration is
10
m
/
s
2
.
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