Question

(6t+1)^2+3=0 pls find0 ​

Answer 1

Answer:

$(6t + 1) {}^{2} + 3 = 0 \\ 36t {}^{2} + 1 + 12t + 3 = 0 \\ 36t {}^{2} + 12t + 4 = 0 \\ 4(9t {}^{2} + 3t + 1) = 0 \\ 9t {}^{2} + 3t + 1 = 0$