Math, asked by Jerrychristian51, 1 year ago

6t - 20 - 32u when t = 6 and u = 1/4

Answers

Answered by poonamrani9765

0

Answer:

hdxiigx

Step-by-step explanation:

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Answered by surya16363

1

Answer:

Given an equation 6t-20-32u

Where t=6 and u=1/4

Step-by-step explanation:

substitute values in the given equation

6t-20-32u=0

where (t=6 and u=1/4)

6(6)-20-32(1/4)

36-20-8=0

36-28=0

8 is your answer

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