Math, asked by ghaznajunaid, 6 months ago

6t2+19t-20 factorise​

Answers

Answered by amanpreetkourkhanuja
3

Step-by-step explanation:

): "t2" was replaced by "t^2".

STEP

1

:

Equation at the end of step 1

((2•3t2) + 19t) - 20

STEP

2

:

Trying to factor by splitting the middle term

2.1 Factoring 6t2+19t-20

The first term is, 6t2 its coefficient is 6 .

The middle term is, +19t its coefficient is 19 .

The last term, "the constant", is -20

Step-1 : Multiply the coefficient of the first term by the constant 6 • -20 = -120

Step-2 : Find two factors of -120 whose sum equals the coefficient of the middle term, which is 19 .

-120 + 1 = -119

-60 + 2 = -58

-40 + 3 = -37

-30 + 4 = -26

-24 + 5 = -19

-20 + 6 = -14

-15 + 8 = -7

-12 + 10 = -2

-10 + 12 = 2

-8 + 15 = 7

-6 + 20 = 14

-5 + 24 = 19 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -5 and 24

6t2 - 5t + 24t - 20

Step-4 : Add up the first 2 terms, pulling out like factors :

t • (6t-5)

Add up the last 2 terms, pulling out common factors :

4 • (6t-5)

Step-5 : Add up the four terms of step 4 :

(t+4) • (6t-5)

Which is the desired factorization

Final result :

(6t - 5) • (t + 4)

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Answered by suddu150903
2

Step-by-step explanation:

.................. Answer is attached......,

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