6t2+19t-20 factorise
Answers
Step-by-step explanation:
): "t2" was replaced by "t^2".
STEP
1
:
Equation at the end of step 1
((2•3t2) + 19t) - 20
STEP
2
:
Trying to factor by splitting the middle term
2.1 Factoring 6t2+19t-20
The first term is, 6t2 its coefficient is 6 .
The middle term is, +19t its coefficient is 19 .
The last term, "the constant", is -20
Step-1 : Multiply the coefficient of the first term by the constant 6 • -20 = -120
Step-2 : Find two factors of -120 whose sum equals the coefficient of the middle term, which is 19 .
-120 + 1 = -119
-60 + 2 = -58
-40 + 3 = -37
-30 + 4 = -26
-24 + 5 = -19
-20 + 6 = -14
-15 + 8 = -7
-12 + 10 = -2
-10 + 12 = 2
-8 + 15 = 7
-6 + 20 = 14
-5 + 24 = 19 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -5 and 24
6t2 - 5t + 24t - 20
Step-4 : Add up the first 2 terms, pulling out like factors :
t • (6t-5)
Add up the last 2 terms, pulling out common factors :
4 • (6t-5)
Step-5 : Add up the four terms of step 4 :
(t+4) • (6t-5)
Which is the desired factorization
Final result :
(6t - 5) • (t + 4)
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Step-by-step explanation:
.................. Answer is attached......,
