Math, asked by purvika75, 3 months ago

6tan^2 theta - 6/cos^2theta​

Answers

Answered by goutamprajapati1444
0

Answer:

6

Step-by-step explanation:

6tan^2 theta - 6/cos^2 theta. (take lcm)

(6tan^2 theta)cos^2 theta - 6

cos^2 theta

6tan^2cos^2 theta - 6. (take 6 as common)

cos^2 theta

6(tan^2cos^2 theta - 1) (tan^2 theta = 1 + sec^2)

cos^2 theta

6((1 + sec^2)cos^2 - 1)

cos^2

6(cos^2 + sec^2cos^2 - 1) (sec theta = 1/cos theta)

cos^2

6(cos^2 +1/cos^2*cos^2 - 1)

cos^2

6(cos^2 + 1 - 1)

cos^2

6(cos^2)

cos^2

6

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