6th 17th term of AP and 19th and 40 respectively
Answers
Answered by
0
Answer:
ANSWER
T
n
=a+(n−1)d
Where a is the first term, d is the common difference and T
n
denotes the n-th term of an AP.
Given:
19=a+5d
41=a+16d
Solving the above equations gives: d=2,a=9
Therefore, T
40
=9+39⋅2=
87
Answered by
0
Answer:
I don't now you can dont now this answerz
Similar questions