Math, asked by jahnavidommadi0403, 10 hours ago

6th root of 12 divided by square root of 3 × cube root of 2
 \sqrt[6]{12}  \div  \sqrt[2]{3}  \times  \sqrt[3]{2}

 if \: \sqrt[n]{a} \:  and \:  \sqrt[n]{b}  \: are \: two \: surds \: of \: same \: order \: then \sqrt[n]{a}  \times  \:  \sqrt[n]{b}  =  \sqrt[n]{a \times b}  \: and \:   \frac{ \sqrt[n]{a} }{ \sqrt[n]{b} }  \:  =  \sqrt[n]{ \frac{a}{b} }  \: where \: b \: is \: not \: equal \: to \: 0

Answers

Answered by asgherade5044
0

Answer:

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