6th standard ICSE board problem in an election 2 candidates a and B are the only contestants if candidate a square 9 lakh 2567 woods and candid b square for 9 lakh 235 words by how much a win or lose solve this in the paper Explain detaily
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Answers
★ Correct question:
In an election 2 candidates A and B are the only contestants. If candidate A scores 9 lakh 2567 votes and candidate B scores 9 lakh 235 votes, By how much a win or lose?
Solution:
In order to solve this question, let's write down the votes scored by both candidates A and B seperately.
- Votes scored by Candidate A = 9,02,567
- Votes scored by Candidate B = 9,00,235
As it can be seen,
Votes scored by Candidate A is greater than the votes scored by Candidate B.
Writing it mathematically,
Votes scored by
Candidate A > Candidate B
So, Candidate A wins the election.
In the question it is asked ‘By how much?’
So to do this subtract:
Candidate A - Candidate B
⇒ 902567 - 900235
⇒ 2332
Conclusion:
∴ Candidate A wins the election by 2332 votes.
SOLUTION :
In order to solve this question, let's write down the votes scored by both candidates A and B seperately.
Votes scored by Candidate A = 9,02,567
Votes scored by Candidate B = 9,00,235
As it can be seen,
Votes scored by Candidate A is greater than the votes scored by Candidate B.
Writing it mathematically,
Votes scored by Candidate A > Candidate B 68
So, Candidate A wins the election.
In the question it is asked 'By how much?'
So , we have to subtract:
Candidate A - Candidate B
→ 902567 - 900235
⇒ 2332
Conclusion:
:: Candidate A wins the election by 2332 votes.