Question

6th term of an Ap is 50 , then find its first 12th term?

Answer 1

Given, a6=50

To find:- first 12th term

answer:-

a6=50

=> a+5d=50

=> a=50-5d.............(1)

First term is :-

a= 50-5d

Second term us :-

a2= a+d

=50-5d+d

=50-4d

Third term is :-

a3=a+2d

=50-5d+2d

=50-3d

Forth term is :-

a4= a+3d

= 50-5d+3d

= 50-2d

Fifth term is :-

a5= a+4d

= 50-5d+4d

= 50 - d

Sixth term is :-

a6= a+ 5d

= 50-5d + 5d

= 50

Seventh term is :-

a7= a+6d

= 50-5d+6d

=50+d

Eighth term is :-

a8= a+7d

= 50-5d+7d

= 50 + 2d

Nineth term is :-

a9= a+8d

= 50-5d+8d

= 50+ 3d

Tenth term is :-

a10= a+ 9d

= 50-5d+9d

=50+ 4d

Eleventh term is :-

a11= a+ 10d

= 50-5d+10d

= 50+ 5d

Twelveth term:-

a12= a+12d

= 50-5d+12d

= 50+7d

$<marquee>❤Ansh❤$

Answer 2

$\huge\underline\mathfrak\purple{Answer}$

Given → a(6)=50

a(6) = 50

a + 5d = 50

a = 50 - 5d

First term →

a= 50-5d

Second term →

a(2)= a + d

=50 - 5d + d

=50 - 4d

Third term →

a(3)=a + 2d

=50 - 5d + 2d

=50 - 3d

Fourth term →

a(4) = a + 3d

= 50 - 5d + 3d

= 50 - 2d

Fifth term →

a(5)= a + 4d

= 50 - 5d + 4d

= 50 - d

Sixth term →

a(6)= a + 5d

= 50 - 5d + 5d

= 50

Seventh term →

a(7)= a + 6d

= 50 - 5d + 6d

=50 + d

Eighth term →

a(8)= a + 7d

= 50 - 5d + 7d

= 50 + 2d

Nineth term →

a(9)= a + 8d

= 50 - 5d + 8d

= 50 + 3d

Tenth term →

a(10)= a + 9d

= 50 - 5d + 9d

=50 + 4d

Eleventh term →

a(11) = a + 10d

= 50 - 5d + 10d

= 50 + 5d

Twelveth term →

a(12) = a + 12d

= 50 - 5d +12d

= 50+7d

Thanks!!