Math, asked by mmamathatv, 1 year ago

6th term of an Ap is 50 , then find its first 12th term?

Answers

Answered by rahulbarge11
0

Answer:

72 is correct answer for you question

Answered by Anonymous
3

Answer:

\bf\red{1st\:term=50-5d}

\bf\red{12th\:term=50+6d}

Step-by-step explanation:

It is being Given that,

6th term of am AP is 50

Now, we know that,

nth term of an AP is Given by

a + (n-1)d

where,

a is first term

a is first term d is common difference

Therefore,

6th term = a + (6-1)d = (a + 5d)

Therefore ,

=> a + 5d = 50

=> a = 50 - 5d

Therefore, first term ( a) of AP is (50-5d)

Similarly,

12th term = a + (12-1)d = (a + 11d)

But,

a = (50-5d)

So, putting the value,

we get,

12th term of AP = (50-5d+11d ) = (50+6d)

Note :- Since the common difference is not known, therefore the specific terms of this AP can't be defined. It will form different AP for different values of common difference (d).

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