Question

6th term of an arithmetic sequence is 19 and its 10th term is 31.a) what is its common difference. b) what is it's first term?

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Answer 1

Answer:

a= 4

d = 3

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Answer 2

Step-by-step explanation:

6th; 19 = a + (6-1) d - - - - - - (1)

10th ; 31 = a +(10-1)d - - - - - - (2)

Solving both eqn:

19 = a + 5d

31 = a + 9d

-_________

-12 = - 4d

d = - 12/ - 4

= 3. Hence common difference is 3.

Putting d =3 in eqn (1)

19 = a + (3×5)

19 = a + 15

a = 4. Hence first term is 4.