6th term of Ap 2,5,8
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in 2,5,8,
a = 2
d = t₂ - t₁ = 5 - 2 = 3
now, n = 6
we know, aₙ = a + ( n - 1 )d
so, a₆ = 2 + (6-1)3
a₆ = 2 + (5)3
a₆ = 2+ 15
a₆ = 17
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Answer:
AP -> 2,5,8,..
a = 2
d = t₂ - t₁ = 5 - 2 = 3
now, n = 6
we know, aₙ = a + ( n - 1 )d
so, a₆ = 2 + (6-1)3
a₆ = 2 + (5)3
a₆ = 2+ 15
a₆ = 17
Thanks..
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