Question

6th term of arithmetic sequence of 19,10th term is 31
Commen difference first term

Answer 1

Answer:

first term = 4

common difference = 3

Explanation:

formula =

an = a1 + (n-1)d

by putting the values

a6 = a1 + ( 6-1)d

19 = a1 +5d. _{1}

a10 = a1 + (10-1)d

31 =a1 + 9d. _{2}

by solving equation 1 and 2 we get d = 3

by the method of elimination

putting d =3 in equation 1 we get A1 = 4