Question

6x+1 \3 +1 =x-3\6 solve the equation and verify your answer​

Answer 1

Answer:

$6x + \frac{1}{3} + 1 = x - \frac{3}{6} \\ = \frac{18x + 1 + 3}{3} = \frac{6x - 3}{6} \\ = \frac{18x + 4}{3} = \frac{6x - 3}{6} \\ by \: cross \: multiplication \: we \: have \\ 6(18x + 4) = 3(6x - 3) \\ = 108x + 24 = 18x - 9 \\ = 108x - 18x = - 9 - 24 \\ = 90x = - 33 \\ = x = \frac{ - 33}{90} \\ = x = \frac{ - 11}{30}$

putting the value at the place of X we have,

$6 \times \frac{ - 11}{30} + \frac{1}{3} + 1</p><p></p><p> = \frac{ - 11}{30} - \frac{3}{6} \\ = \frac{ - 11}{5} + \frac{1}{3} + 1 = \frac{ - 11}{30} - \frac{3}{6} \\ = \frac{ - 33 + 5 + 15}{15} = \frac{ - 11 - 15}{30} \\ = \frac{ - 13}{15} = \frac{ - 26}{30} \\ = \frac{ - 13}{15} = \frac{ - 13}{15}$

L.H.S=R.H.S

Step-by-step explanation:

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Answer 2

Answer:

7/11

Step-by-step explanation:

lets first change the denomintor to be the same

so it becomes

2(6x+1)/3x2

which is equal to

12x+2+x-3/6=1

then we transpose

12x-x + 2-3/6= 1

11x-1+6

11x=6+1

11x=7

x= 7/11