Math, asked by swaranjoshio6, 3 months ago


(6x + 1/3) ( 6x - 1/3) ​

Answers

Answered by TotalCoaI
1

➭ HeY TheRe!

It is given to solve the given problem;

 \tt(6x +  \frac{1}{3} )(6x -  \frac{1}{3} ) \\

 \to \tt \: \left(6x\right)^{2}-\left(\frac{1}{3}\right)^{2}  \:\\

  \tt \to \: 6^{2}x^{2}-\left(\frac{1}{3}\right)^{2}  \: \\

 \tt \to \: 36x^{2}-\left(\frac{1}{3}\right)^{2}  \: \\

 \tt \fbox{\fbox{\to \: 36x^{2}-\frac{1}{9} }} \:\\

➙ Here, the solution for  \sf(6x +  \frac{1}{3} )(6x -  \frac{1}{3} )  will be  \sf36x^{2}-\frac{1}{9}  \:.

Answered by satyam09s0205
0

Step-by-step explanation:

If A × B ={(1,2),(1,3),(3,2),(3,3),(5,2),(5,3)} and B × A = {(2,1),(2,3),(2,5),(3,1),(3,3),(3,5)} Is A×B =B×A ? If not why?

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