Question

6x^2+11x+3=0
please solve​

Answer 1

Step-by-step explanation:

hope it helps..........

Answer 2

Answer:

$x = - \frac{3}{2} \: \: or \: \: - \frac{1}{3}$

Step-by-step explanation:

$6 {x}^{2} + 11x + 3 = 0 \\ \\ \therefore \: 6 {x}^{2} + 2x + 9x + 3 = 0 \\ \\ \therefore \: 2x(3x + 1) + 3(3x + 1) = 0 \\ \\ \therefore \: (2x + 3)(3x + 1) = 0 \\ \\ \therefore \: 2x + 3 = 0 \: \: \: or \: \: \: 3x + 1 = 0 \\ \\ \: 2x + 3 = 0 \\ \\ \therefore2x = - 3 \\ \\ \therefore \: x = - \frac{3}{2} ......ans(1) \\ \\ 3x + 1 = 0 \\ \\ \therefore \: 3x = - 1 \\ \\ \therefore \: x = - \frac{1}{3} .....ans(2)$