Math, asked by shiprasingh51323, 20 days ago

6x^2-13x+5=0 completing square

Answers

Answered by swagatabasak277
0

Answer:

5/3, 1/2

Step-by-step explanation:

6x^2 - 10x - 3x + 5 = 0

=) 2x(3x - 5) - 1(3x-5) = 0

=) (3x - 5) (2x - 1) = 0

=) x = 5/3, 1/2 (Ans)

Answered by rivabera90
0

Answer:

6x^2-13x+5=0

6x^2-(-15+2)x+5=0

6x^2+15x-2x+5=0

3x(2x+5)-1(2x-5)=0

(3x-1)(2x+5)(2x-5)=0

x=-1/3,,x=5/2,,x=-5/2

or explain by sridhar acharyo law

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