6x^2_13x+5=0.
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6x²-13x+5=0,
and a=6 ,b=-13, c=5
so, basis of the formula of Sridhar Acharya,
X= -b+_√b²-4ac
_______
2a
= -(-13)+_√(-13)²-4.6.5
_____________
12
= 13+_√339-120
_________
12
= 13+_√219
______
12
.
. . either, X= 13+√219 13-√219
--------- or, ---------
12 12
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