Question

-6x^2+13x-5 factorise algebraic expressions​

Answer 1

Answer:

$= > - 6 {x}^{2} + 13x - 5 \\ \\ = > - 6 {x}^{2} + (3 + 10)x - 5 \\ \\ = > - 6 {x}^{2} + 3 x + 10x - 5 \\ \\ = > - 3x(2x - 1) + 5(2x - 1) \\ \\ = > (2x - 1)(5 - 3x)$

Answer 2

Answer:

The factorization of the algebraic expression; $-6x^{2} +13x - 5$ is

(-2x + 1)(3x - 5).

Step-by-step explanation:

Given algebraic expression;

$-6x^{2} +13x - 5$

We multiply the coefficient of x(-6) and the constant(-5), and calculate the factors. We then split the middle term using all the factors of the product.

= $-6x^{2}$ + (10 + 3)x - 5

= $-6x^{2}$ + 10x + 3x - 5

= -2x(3x - 5) + 1(3x -5)

= (-2x + 1)(3x - 5)

The factorization of the algebraic expression; $-6x^{2} +13x - 5$ is

(-2x + 1)(3x - 5).