6x^2+13x-5 . factorise it
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6x^2+13x-5 | Mathway
For a polynomial of the form ax2+bx+c a x 2 + b x + c , rewrite the middle term as a sum of two terms whose product is a⋅c=6⋅−5=−30 a ⋅ c = 6 ⋅ - 5 = - 30 and whose sum is b=13 . Factor 13 13 out of 13x 13 x . Factor out the greatest common factor from each group.
For a polynomial of the form ax2+bx+c a x 2 + b x + c , rewrite the middle term as a sum of two terms whose product is a⋅c=6⋅−5=−30 a ⋅ c = 6 ⋅ - 5 = - 30 and whose sum is b=13 . Factor 13 13 out of 13x 13 x . Factor out the greatest common factor from each group.
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14
Answer:
Hence, the values of
x = 1/3 , -5/2
Step-by-step explanation:
Given,
P(x) = 6x^2 + 13 - 5
By using the splitting the middle term method, we get,
=> 6x^2 - 2x + 15x - 5 = 0
=> 2x(3x - 1) + 5(3x - 1) = 0
=> (2x + 5)(3x - 1) = 0
Here, either (2x + 5) = 0 or (3x - 1) = 0
For the values of x,
(2x + 5) = 0
=> 2x = -5
=> x = -5/2
(3x - 1) = 0
=> 3x = 1
=> x = 1/3
Hence, the values of
x = 1/3 , -5/2
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