6x^2+17x+12 factorise the following equation
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Answer :
- 6x² + 17x + 12 = (2x + 3) (3x + 4)
Given :
- 6x² + 17x + 12
To find :
- Factor
Solution :
》6x² + 17x + 12
》6x² + 8x + 9x + 12
》2x(3x + 4) + 3(3x + 4)
》(2x + 3) (3x + 4)
Hence, 6x² + 17x + 12 = (2x + 3) (3x + 4)
Or
Explanation :
Given that, co - effiecent of x² is 6 and constant is 12 Now we have to find this two co-effiecent of product = 6 × 12 = 72 and middle term co-effiecent is 17
And Given that factor 72 so we have to sum of these factors is 17 then, 8 × 9 = 72 and 8 + 9 = 17
》6x² + 17x + 12
》6x² + 8x + 9x + 12
》2x(3x + 4) + 3(3x + 4)
》(2x + 3) (3x + 4)
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