6x^2+19-22 by x+2 pls answer
Answers
Answer:
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Step-by-step explanation:
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Step by step solution :
STEP
1
:
Equation at the end of step 1
((2•3x2) - 19x) - 11 = 0
STEP
2
:
Trying to factor by splitting the middle term
2.1 Factoring 6x2-19x-11
The first term is, 6x2 its coefficient is 6 .
The middle term is, -19x its coefficient is -19 .
The last term, "the constant", is -11
Step-1 : Multiply the coefficient of the first term by the constant 6 • -11 = -66
Step-2 : Find two factors of -66 whose sum equals the coefficient of the middle term, which is -19 .
-66 + 1 = -65
-33 + 2 = -31
-22 + 3 = -19 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -22 and 3
6x2 - 22x + 3x - 11
Step-4 : Add up the first 2 terms, pulling out like factors :
2x • (3x-11)
Add up the last 2 terms, pulling out common factors :
1 • (3x-11)
Step-5 : Add up the four terms of step 4 :
(2x+1) • (3x-11)
Which is the desired factorization
Equation at the end of step
2
:
(3x - 11) • (2x + 1) = 0
STEP
3
:
Theory - Roots of a product
3.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.