6x^2-19x-7 anyone know how to solve it
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6x^2-19x-7= 6x^x+2x-21x-7= 2x (3x-1)-7 (3x-1)=(2x-7)(3x-1)
if the expression is =0 then; (2x-7)(3x-1)=0 then x=7/2 or x=1/3 this is the value of x
if the expression is =0 then; (2x-7)(3x-1)=0 then x=7/2 or x=1/3 this is the value of x
utsav786:
no bro its complete
the expression must be equals to 0 or something..otherwise how I can calculate the value of x???
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