6x^2-√2-2=0 Find roots by prime factorisation
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6x² + 2√2x - 3√2x - 2 = 0
2x(3x + √2) - √2(3x + √2) = 0
(2x - √2) (3x + √2) = 0
I hope this is what you are asking for. If you are asking for the value of x, the x = √2/2 & - √2/3
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