Question

6x^2 – 2 (x + 1) at x = – 4

Answer 1

Answer:

102

Step-by-step explanation:

6x^2 – 2 (x + 1) at x = – 4

=6 (-4)^2 - 2 (-4+1)

= 6 x 16 -2 ( -3)

= 96 - (-6)

=96+6

=102

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Answer 2

$6x^2 – 2 (x + 1)$

$\huge\tt{<u>G</u><u>i</u><u>v</u><u>e</u><u>n</u>}$

x = -4

$\huge\tt\red{ Answer}$

$6x^2 – 2 (x + 1)$

$6 {x}^{2} - 2x - 2$

Put the value. Replace x by -4

$6 {( - 4)}^{2} - 2( - 4) - 2$

A square of negative no. becomes positive.

That is (-4)×(-4) = +16

$6(16) + 8 - 2$

$96 + 8 - 2$

$= 102$

$\huge\tt\orange{Additional~Information}$

The signs are changed on the following bases=}

(-) (-) = +

(+) (+) = +

(+) (-) = -

(-) (+) = -