Question

6x^2-√2x-2=0
Find the roots of the quadratic equation by using factorisation method.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Concept introduction:

The word "quadratic" which comes from quadratum is a latin word for means squre and quadratic equation means there should be a squre term and  no term in which it is raised to a higher power.

Given:

Here the equation given to us is $6x^2-\sqrt{2}x -2=0$.

To find:

We have to find the roots of the quadratic equation by using factorisation method.

Solution:

According to the question,

$6x^2-\sqrt{2}x -2=0$

$- > 6x^{2}-3\sqrt{2}x+2\sqrt{2}x -2=0\\ - > 3\sqrt{2}x(\sqrt{2}x-1)+2(\sqrt{2}x-1)=0\\- > (\sqrt{2}x-1)(3\sqrt{2}x+2)=0\\- > \sqrt{2}x-1=0 \\- > x=\frac{1}{\sqrt{2} }$ or

$3\sqrt{2}x+2=0\\ - > x=-\frac{2}{3\sqrt{2} }$

So, the final answer is $\frac{1}{\sqrt{2} }$ and $-\frac{2}{3\sqrt{2} }$.