Question

6x^2 - 3 - 7x
by splitting the middile term.. with steps ​

Answer 1

here is your answer dude:

6x²-7x-3=0

6x²-9x+2x-3=0

3x(2x-3)+1(2x-3)=0

(3x+1)(2x-3)=0

x= -1/3 and x= 3/2

Answer 2

Answer:

$\Large{\underline{\underline{\bf{Solutions:-}}}}$

$6 {x}^{2} - 3 - 7x \\ \\ 6 {x}^{2} + 2x - 9x - 3 \\ \\ 2x(3x + 1) - 3(3x + 1) \\ \\ (2x - 3)(3x + 1)$

$\huge\mathfrak\green{Thanks}$