6x^2+3x^2-5x+1 , What is the sum of the integers of the zeros of this polynomial number?
Answers
Answered by
1
Answer:
6x^2+3x^2×-5x+1
= 9x^2-5x+1 answer
Answered by
1
Answer:
5
Step-by-step explanation:
If α and β are zeros, polynomial can be expressed as
x² - (α +β)x + αβ
In the given polynomial
6x² + 3x² - 5x + 1
⇒ 9x² -5x +1
The co-efficent of -x is the sum of zeros which is 5.
Similar questions