Question

6x^2 + 7 root 2 x + 4

Answer 1

6x² + 7√2x + 4

6x² + 4√2x + 3√2x + 4

2x(3x + 2√2) + √2(3x + 2√2)

(2x + √2)(3x + 2√2)

X = -√2/2 , x = -2√2/3

X = -1/√2 , x = -2√2/3

Answer 2

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✴✴$\underline{Here \: is \: your \: answer↓}$⬇⏬⤵

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▶⏩$\boxed{Factorise:-)}$

↪➡$\bf{6 {x}^{2} + 7 \sqrt{2}x + 4.}$

↪➡$\bf{6 {x}^{2} + 4 \sqrt{2}x + 3 \sqrt{2}x + 4.}$

↪➡$\bf{2x(3x + 2 \sqrt{2} ) + \sqrt{2} (3x + 2 \sqrt{2} ).}$

↪➡$\bf{(2x + \sqrt{2} ) \: (3x + 2 \sqrt{2} ).}$

↪➡$\bf{2x + \sqrt{2} = 0 \: | \: 3x + 2 \sqrt{2} = 0.}$

↪➡$\bf{x = \frac{ - \sqrt{2} }{2} \: | \: x = \frac{ - 2 \sqrt{2} }{3} .}$

$\underline{Or}$

↪➡$\boxed{x = \frac{ - 1}{ \sqrt{2} } \: | \: x = \frac{ - 2 \sqrt{2} }{3} .}$

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✴✴$\boxed{THANKS}$✴✴

☺☺☺$\underline{Hope \: it \: is \: helpful \: for \: you}$✌✌✌.