Question

6x^2-7x-1=0 solve by quadratic formula plz explain n give correct ans​

Answer 1

Answer:

$6 {x}^{2} - 7x - 1 = 0 \\ \\ = > 6 {x}^{2} - (6 + 1)x - 1 = 0 \\ \\ = > 6 {x}^{2} - 6x - x - 1 = 0 \\ \\ = > 6x(x - 1) - 1(x - 1) = 0 \\ \\ = > (6x - 1)(x - 1) = 0 \\ \\ either \: 6x - 1 = 0 \\ \\ = > 6x = 1 \\ \\ = > x = \frac{1}{6} \\ \\ or \: x - 1 = 0 \\ \\ = > x = 1$

hope this much helps uh ❣️