6x^2+7x-13=0 solve by factorisation method
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Answered by
2
Answer:
6x²+7x -13= 0
=> 6x²+13x-6x-13= 0
=> x(6x+13) -1(x+13) = 0
=> (6x+13) (x-1) = 0
Answered by
1
Answer:
6x^2 +7x -13 =0
product = -78x^2 (6x^2 × -13)
sum = +7x
factors = 13x and -6x ( two numbers when multiplied, gives -78x^2 and when added gives +7x)
replace +7x with 13x and -6x
6x^2 +13x -6x -13 =0
collect like terms
6x^2 -6x +13x-13 =0
factorize
6x (x-1) + 13 (×-1) = 0
the factors are (x-1) twice
if x-1 = 0 then, x = 1
therefore, the factors are 1 twice
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