Question

6x^2-7x+3 find zeroes​

Answer 1

Step-by-step explanation:

${6x}^{2} - 7x - 3 \\ = {6x}^{2} -9x + 2x - 3$

=3x(2x-3)-1 (2x-3)

=(2x-3)(3x-1)

=>x=3/2 or x=1/3

i feel the q is not correct the proper questions must be 6x^2-7x-3

or

6x^2+7x+3

Answer 2

i think there is something wrong

it would be 6x² - 7x - 3.

answer:

zeros are : 3/2 and -1/2

explanation:

= 6x² - 7x - 3

= 6x² - 9x + 2x - 3

= 3x ( 2x - 3 ) + 1 ( 2x -3 )

= (2x-3) (3x+1)

2x-3=0 and 3x+1=0

2x= 3 3x= -1

x = 3/2 x = -1/3

hope it will help u ❣️