Question

6x^2-7x+9=0, find the value of x​

Answer 1

Step-by-step explanation:

Please check whether your question is right.

Answer 2

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

➙6x²-7x+9

It can be solved through either splitting the middle term or by through quadratic formula.

Here ,we are unable to find its factors of middle term so,we can do by using quadratic formula.

a= 6,b= -7 , c= 9

It can be solve through quadratic formula

x= -b±√b²-4ac ÷ 2a

➙x= -(-7)±√ (-7)²-4(6)(9)/2(6)

➙x= 7±√49-216/12

➙x= 7±√-167/12

Here,the discriminant is >0

So,there are two complex roots

iota [ i ] is used in place of negative values whenever is inside the root.

➙x= 7±√167i /12

➙x=7/12±√167i/12

➙x= 0.58+1.07i

➙x= 0.58-1.07i