6x^2+9x-8=0 factorize it
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6x2-9x-8 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = 6
B = -9
C = -8
Accordingly, B2 - 4AC =
81 - (-192) =
273
Applying the quadratic formula :
9 ± √ 273
x = —————
12
√ 273 , rounded to 4 decimal digits, is 16.5227
So now we are looking at:
x = ( 9 ± 16.523 ) / 12
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